3.9.75 \(\int \frac {x \arctan (a x)^{5/2}}{(c+a^2 c x^2)^3} \, dx\) [875]

3.9.75.1 Optimal result
3.9.75.2 Mathematica [C] (verified)
3.9.75.3 Rubi [A] (verified)
3.9.75.4 Maple [A] (verified)
3.9.75.5 Fricas [F(-2)]
3.9.75.6 Sympy [F]
3.9.75.7 Maxima [F(-2)]
3.9.75.8 Giac [F]
3.9.75.9 Mupad [F(-1)]

3.9.75.1 Optimal result

Integrand size = 22, antiderivative size = 254 \[ \int \frac {x \arctan (a x)^{5/2}}{\left (c+a^2 c x^2\right )^3} \, dx=-\frac {225 \sqrt {\arctan (a x)}}{2048 a^2 c^3}+\frac {15 \sqrt {\arctan (a x)}}{256 a^2 c^3 \left (1+a^2 x^2\right )^2}+\frac {45 \sqrt {\arctan (a x)}}{256 a^2 c^3 \left (1+a^2 x^2\right )}+\frac {5 x \arctan (a x)^{3/2}}{32 a c^3 \left (1+a^2 x^2\right )^2}+\frac {15 x \arctan (a x)^{3/2}}{64 a c^3 \left (1+a^2 x^2\right )}+\frac {3 \arctan (a x)^{5/2}}{32 a^2 c^3}-\frac {\arctan (a x)^{5/2}}{4 a^2 c^3 \left (1+a^2 x^2\right )^2}-\frac {15 \sqrt {\frac {\pi }{2}} \operatorname {FresnelC}\left (2 \sqrt {\frac {2}{\pi }} \sqrt {\arctan (a x)}\right )}{4096 a^2 c^3}-\frac {15 \sqrt {\pi } \operatorname {FresnelC}\left (\frac {2 \sqrt {\arctan (a x)}}{\sqrt {\pi }}\right )}{256 a^2 c^3} \]

output
5/32*x*arctan(a*x)^(3/2)/a/c^3/(a^2*x^2+1)^2+15/64*x*arctan(a*x)^(3/2)/a/c 
^3/(a^2*x^2+1)+3/32*arctan(a*x)^(5/2)/a^2/c^3-1/4*arctan(a*x)^(5/2)/a^2/c^ 
3/(a^2*x^2+1)^2-15/8192*FresnelC(2*2^(1/2)/Pi^(1/2)*arctan(a*x)^(1/2))*2^( 
1/2)*Pi^(1/2)/a^2/c^3-15/256*FresnelC(2*arctan(a*x)^(1/2)/Pi^(1/2))*Pi^(1/ 
2)/a^2/c^3-225/2048*arctan(a*x)^(1/2)/a^2/c^3+15/256*arctan(a*x)^(1/2)/a^2 
/c^3/(a^2*x^2+1)^2+45/256*arctan(a*x)^(1/2)/a^2/c^3/(a^2*x^2+1)
 
3.9.75.2 Mathematica [C] (verified)

Result contains complex when optimal does not.

Time = 0.56 (sec) , antiderivative size = 359, normalized size of antiderivative = 1.41 \[ \int \frac {x \arctan (a x)^{5/2}}{\left (c+a^2 c x^2\right )^3} \, dx=\frac {450 \sqrt {2 \pi } \operatorname {FresnelC}\left (2 \sqrt {\frac {2}{\pi }} \sqrt {\arctan (a x)}\right )+\frac {16320 \arctan (a x)-5760 a^2 x^2 \arctan (a x)-14400 a^4 x^4 \arctan (a x)+51200 a x \arctan (a x)^2+30720 a^3 x^3 \arctan (a x)^2-20480 \arctan (a x)^3+24576 a^2 x^2 \arctan (a x)^3+12288 a^4 x^4 \arctan (a x)^3-3600 \sqrt {\pi } \left (1+a^2 x^2\right )^2 \sqrt {\arctan (a x)} \operatorname {FresnelC}\left (\frac {2 \sqrt {\arctan (a x)}}{\sqrt {\pi }}\right )+1020 i \sqrt {2} \left (1+a^2 x^2\right )^2 \sqrt {-i \arctan (a x)} \Gamma \left (\frac {1}{2},-2 i \arctan (a x)\right )-1020 i \sqrt {2} \left (1+a^2 x^2\right )^2 \sqrt {i \arctan (a x)} \Gamma \left (\frac {1}{2},2 i \arctan (a x)\right )+345 i \left (1+a^2 x^2\right )^2 \sqrt {-i \arctan (a x)} \Gamma \left (\frac {1}{2},-4 i \arctan (a x)\right )-345 i \left (1+a^2 x^2\right )^2 \sqrt {i \arctan (a x)} \Gamma \left (\frac {1}{2},4 i \arctan (a x)\right )}{\left (1+a^2 x^2\right )^2 \sqrt {\arctan (a x)}}}{131072 a^2 c^3} \]

input
Integrate[(x*ArcTan[a*x]^(5/2))/(c + a^2*c*x^2)^3,x]
 
output
(450*Sqrt[2*Pi]*FresnelC[2*Sqrt[2/Pi]*Sqrt[ArcTan[a*x]]] + (16320*ArcTan[a 
*x] - 5760*a^2*x^2*ArcTan[a*x] - 14400*a^4*x^4*ArcTan[a*x] + 51200*a*x*Arc 
Tan[a*x]^2 + 30720*a^3*x^3*ArcTan[a*x]^2 - 20480*ArcTan[a*x]^3 + 24576*a^2 
*x^2*ArcTan[a*x]^3 + 12288*a^4*x^4*ArcTan[a*x]^3 - 3600*Sqrt[Pi]*(1 + a^2* 
x^2)^2*Sqrt[ArcTan[a*x]]*FresnelC[(2*Sqrt[ArcTan[a*x]])/Sqrt[Pi]] + (1020* 
I)*Sqrt[2]*(1 + a^2*x^2)^2*Sqrt[(-I)*ArcTan[a*x]]*Gamma[1/2, (-2*I)*ArcTan 
[a*x]] - (1020*I)*Sqrt[2]*(1 + a^2*x^2)^2*Sqrt[I*ArcTan[a*x]]*Gamma[1/2, ( 
2*I)*ArcTan[a*x]] + (345*I)*(1 + a^2*x^2)^2*Sqrt[(-I)*ArcTan[a*x]]*Gamma[1 
/2, (-4*I)*ArcTan[a*x]] - (345*I)*(1 + a^2*x^2)^2*Sqrt[I*ArcTan[a*x]]*Gamm 
a[1/2, (4*I)*ArcTan[a*x]])/((1 + a^2*x^2)^2*Sqrt[ArcTan[a*x]]))/(131072*a^ 
2*c^3)
 
3.9.75.3 Rubi [A] (verified)

Time = 1.34 (sec) , antiderivative size = 286, normalized size of antiderivative = 1.13, number of steps used = 14, number of rules used = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.591, Rules used = {5465, 27, 5435, 5427, 5439, 3042, 3793, 2009, 5465, 5439, 3042, 3793, 2009}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {x \arctan (a x)^{5/2}}{\left (a^2 c x^2+c\right )^3} \, dx\)

\(\Big \downarrow \) 5465

\(\displaystyle \frac {5 \int \frac {\arctan (a x)^{3/2}}{c^3 \left (a^2 x^2+1\right )^3}dx}{8 a}-\frac {\arctan (a x)^{5/2}}{4 a^2 c^3 \left (a^2 x^2+1\right )^2}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {5 \int \frac {\arctan (a x)^{3/2}}{\left (a^2 x^2+1\right )^3}dx}{8 a c^3}-\frac {\arctan (a x)^{5/2}}{4 a^2 c^3 \left (a^2 x^2+1\right )^2}\)

\(\Big \downarrow \) 5435

\(\displaystyle \frac {5 \left (-\frac {3}{64} \int \frac {1}{\left (a^2 x^2+1\right )^3 \sqrt {\arctan (a x)}}dx+\frac {3}{4} \int \frac {\arctan (a x)^{3/2}}{\left (a^2 x^2+1\right )^2}dx+\frac {x \arctan (a x)^{3/2}}{4 \left (a^2 x^2+1\right )^2}+\frac {3 \sqrt {\arctan (a x)}}{32 a \left (a^2 x^2+1\right )^2}\right )}{8 a c^3}-\frac {\arctan (a x)^{5/2}}{4 a^2 c^3 \left (a^2 x^2+1\right )^2}\)

\(\Big \downarrow \) 5427

\(\displaystyle \frac {5 \left (-\frac {3}{64} \int \frac {1}{\left (a^2 x^2+1\right )^3 \sqrt {\arctan (a x)}}dx+\frac {3}{4} \left (-\frac {3}{4} a \int \frac {x \sqrt {\arctan (a x)}}{\left (a^2 x^2+1\right )^2}dx+\frac {x \arctan (a x)^{3/2}}{2 \left (a^2 x^2+1\right )}+\frac {\arctan (a x)^{5/2}}{5 a}\right )+\frac {x \arctan (a x)^{3/2}}{4 \left (a^2 x^2+1\right )^2}+\frac {3 \sqrt {\arctan (a x)}}{32 a \left (a^2 x^2+1\right )^2}\right )}{8 a c^3}-\frac {\arctan (a x)^{5/2}}{4 a^2 c^3 \left (a^2 x^2+1\right )^2}\)

\(\Big \downarrow \) 5439

\(\displaystyle \frac {5 \left (-\frac {3 \int \frac {1}{\left (a^2 x^2+1\right )^2 \sqrt {\arctan (a x)}}d\arctan (a x)}{64 a}+\frac {3}{4} \left (-\frac {3}{4} a \int \frac {x \sqrt {\arctan (a x)}}{\left (a^2 x^2+1\right )^2}dx+\frac {x \arctan (a x)^{3/2}}{2 \left (a^2 x^2+1\right )}+\frac {\arctan (a x)^{5/2}}{5 a}\right )+\frac {x \arctan (a x)^{3/2}}{4 \left (a^2 x^2+1\right )^2}+\frac {3 \sqrt {\arctan (a x)}}{32 a \left (a^2 x^2+1\right )^2}\right )}{8 a c^3}-\frac {\arctan (a x)^{5/2}}{4 a^2 c^3 \left (a^2 x^2+1\right )^2}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {5 \left (\frac {3}{4} \left (-\frac {3}{4} a \int \frac {x \sqrt {\arctan (a x)}}{\left (a^2 x^2+1\right )^2}dx+\frac {x \arctan (a x)^{3/2}}{2 \left (a^2 x^2+1\right )}+\frac {\arctan (a x)^{5/2}}{5 a}\right )-\frac {3 \int \frac {\sin \left (\arctan (a x)+\frac {\pi }{2}\right )^4}{\sqrt {\arctan (a x)}}d\arctan (a x)}{64 a}+\frac {x \arctan (a x)^{3/2}}{4 \left (a^2 x^2+1\right )^2}+\frac {3 \sqrt {\arctan (a x)}}{32 a \left (a^2 x^2+1\right )^2}\right )}{8 a c^3}-\frac {\arctan (a x)^{5/2}}{4 a^2 c^3 \left (a^2 x^2+1\right )^2}\)

\(\Big \downarrow \) 3793

\(\displaystyle \frac {5 \left (\frac {3}{4} \left (-\frac {3}{4} a \int \frac {x \sqrt {\arctan (a x)}}{\left (a^2 x^2+1\right )^2}dx+\frac {x \arctan (a x)^{3/2}}{2 \left (a^2 x^2+1\right )}+\frac {\arctan (a x)^{5/2}}{5 a}\right )-\frac {3 \int \left (\frac {\cos (2 \arctan (a x))}{2 \sqrt {\arctan (a x)}}+\frac {\cos (4 \arctan (a x))}{8 \sqrt {\arctan (a x)}}+\frac {3}{8 \sqrt {\arctan (a x)}}\right )d\arctan (a x)}{64 a}+\frac {x \arctan (a x)^{3/2}}{4 \left (a^2 x^2+1\right )^2}+\frac {3 \sqrt {\arctan (a x)}}{32 a \left (a^2 x^2+1\right )^2}\right )}{8 a c^3}-\frac {\arctan (a x)^{5/2}}{4 a^2 c^3 \left (a^2 x^2+1\right )^2}\)

\(\Big \downarrow \) 2009

\(\displaystyle \frac {5 \left (\frac {3}{4} \left (-\frac {3}{4} a \int \frac {x \sqrt {\arctan (a x)}}{\left (a^2 x^2+1\right )^2}dx+\frac {x \arctan (a x)^{3/2}}{2 \left (a^2 x^2+1\right )}+\frac {\arctan (a x)^{5/2}}{5 a}\right )+\frac {x \arctan (a x)^{3/2}}{4 \left (a^2 x^2+1\right )^2}+\frac {3 \sqrt {\arctan (a x)}}{32 a \left (a^2 x^2+1\right )^2}-\frac {3 \left (\frac {1}{8} \sqrt {\frac {\pi }{2}} \operatorname {FresnelC}\left (2 \sqrt {\frac {2}{\pi }} \sqrt {\arctan (a x)}\right )+\frac {1}{2} \sqrt {\pi } \operatorname {FresnelC}\left (\frac {2 \sqrt {\arctan (a x)}}{\sqrt {\pi }}\right )+\frac {3}{4} \sqrt {\arctan (a x)}\right )}{64 a}\right )}{8 a c^3}-\frac {\arctan (a x)^{5/2}}{4 a^2 c^3 \left (a^2 x^2+1\right )^2}\)

\(\Big \downarrow \) 5465

\(\displaystyle \frac {5 \left (\frac {3}{4} \left (-\frac {3}{4} a \left (\frac {\int \frac {1}{\left (a^2 x^2+1\right )^2 \sqrt {\arctan (a x)}}dx}{4 a}-\frac {\sqrt {\arctan (a x)}}{2 a^2 \left (a^2 x^2+1\right )}\right )+\frac {x \arctan (a x)^{3/2}}{2 \left (a^2 x^2+1\right )}+\frac {\arctan (a x)^{5/2}}{5 a}\right )+\frac {x \arctan (a x)^{3/2}}{4 \left (a^2 x^2+1\right )^2}+\frac {3 \sqrt {\arctan (a x)}}{32 a \left (a^2 x^2+1\right )^2}-\frac {3 \left (\frac {1}{8} \sqrt {\frac {\pi }{2}} \operatorname {FresnelC}\left (2 \sqrt {\frac {2}{\pi }} \sqrt {\arctan (a x)}\right )+\frac {1}{2} \sqrt {\pi } \operatorname {FresnelC}\left (\frac {2 \sqrt {\arctan (a x)}}{\sqrt {\pi }}\right )+\frac {3}{4} \sqrt {\arctan (a x)}\right )}{64 a}\right )}{8 a c^3}-\frac {\arctan (a x)^{5/2}}{4 a^2 c^3 \left (a^2 x^2+1\right )^2}\)

\(\Big \downarrow \) 5439

\(\displaystyle \frac {5 \left (\frac {3}{4} \left (-\frac {3}{4} a \left (\frac {\int \frac {1}{\left (a^2 x^2+1\right ) \sqrt {\arctan (a x)}}d\arctan (a x)}{4 a^2}-\frac {\sqrt {\arctan (a x)}}{2 a^2 \left (a^2 x^2+1\right )}\right )+\frac {x \arctan (a x)^{3/2}}{2 \left (a^2 x^2+1\right )}+\frac {\arctan (a x)^{5/2}}{5 a}\right )+\frac {x \arctan (a x)^{3/2}}{4 \left (a^2 x^2+1\right )^2}+\frac {3 \sqrt {\arctan (a x)}}{32 a \left (a^2 x^2+1\right )^2}-\frac {3 \left (\frac {1}{8} \sqrt {\frac {\pi }{2}} \operatorname {FresnelC}\left (2 \sqrt {\frac {2}{\pi }} \sqrt {\arctan (a x)}\right )+\frac {1}{2} \sqrt {\pi } \operatorname {FresnelC}\left (\frac {2 \sqrt {\arctan (a x)}}{\sqrt {\pi }}\right )+\frac {3}{4} \sqrt {\arctan (a x)}\right )}{64 a}\right )}{8 a c^3}-\frac {\arctan (a x)^{5/2}}{4 a^2 c^3 \left (a^2 x^2+1\right )^2}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {5 \left (\frac {3}{4} \left (-\frac {3}{4} a \left (\frac {\int \frac {\sin \left (\arctan (a x)+\frac {\pi }{2}\right )^2}{\sqrt {\arctan (a x)}}d\arctan (a x)}{4 a^2}-\frac {\sqrt {\arctan (a x)}}{2 a^2 \left (a^2 x^2+1\right )}\right )+\frac {x \arctan (a x)^{3/2}}{2 \left (a^2 x^2+1\right )}+\frac {\arctan (a x)^{5/2}}{5 a}\right )+\frac {x \arctan (a x)^{3/2}}{4 \left (a^2 x^2+1\right )^2}+\frac {3 \sqrt {\arctan (a x)}}{32 a \left (a^2 x^2+1\right )^2}-\frac {3 \left (\frac {1}{8} \sqrt {\frac {\pi }{2}} \operatorname {FresnelC}\left (2 \sqrt {\frac {2}{\pi }} \sqrt {\arctan (a x)}\right )+\frac {1}{2} \sqrt {\pi } \operatorname {FresnelC}\left (\frac {2 \sqrt {\arctan (a x)}}{\sqrt {\pi }}\right )+\frac {3}{4} \sqrt {\arctan (a x)}\right )}{64 a}\right )}{8 a c^3}-\frac {\arctan (a x)^{5/2}}{4 a^2 c^3 \left (a^2 x^2+1\right )^2}\)

\(\Big \downarrow \) 3793

\(\displaystyle \frac {5 \left (\frac {3}{4} \left (-\frac {3}{4} a \left (\frac {\int \left (\frac {\cos (2 \arctan (a x))}{2 \sqrt {\arctan (a x)}}+\frac {1}{2 \sqrt {\arctan (a x)}}\right )d\arctan (a x)}{4 a^2}-\frac {\sqrt {\arctan (a x)}}{2 a^2 \left (a^2 x^2+1\right )}\right )+\frac {x \arctan (a x)^{3/2}}{2 \left (a^2 x^2+1\right )}+\frac {\arctan (a x)^{5/2}}{5 a}\right )+\frac {x \arctan (a x)^{3/2}}{4 \left (a^2 x^2+1\right )^2}+\frac {3 \sqrt {\arctan (a x)}}{32 a \left (a^2 x^2+1\right )^2}-\frac {3 \left (\frac {1}{8} \sqrt {\frac {\pi }{2}} \operatorname {FresnelC}\left (2 \sqrt {\frac {2}{\pi }} \sqrt {\arctan (a x)}\right )+\frac {1}{2} \sqrt {\pi } \operatorname {FresnelC}\left (\frac {2 \sqrt {\arctan (a x)}}{\sqrt {\pi }}\right )+\frac {3}{4} \sqrt {\arctan (a x)}\right )}{64 a}\right )}{8 a c^3}-\frac {\arctan (a x)^{5/2}}{4 a^2 c^3 \left (a^2 x^2+1\right )^2}\)

\(\Big \downarrow \) 2009

\(\displaystyle \frac {5 \left (\frac {3}{4} \left (-\frac {3}{4} a \left (\frac {\frac {1}{2} \sqrt {\pi } \operatorname {FresnelC}\left (\frac {2 \sqrt {\arctan (a x)}}{\sqrt {\pi }}\right )+\sqrt {\arctan (a x)}}{4 a^2}-\frac {\sqrt {\arctan (a x)}}{2 a^2 \left (a^2 x^2+1\right )}\right )+\frac {x \arctan (a x)^{3/2}}{2 \left (a^2 x^2+1\right )}+\frac {\arctan (a x)^{5/2}}{5 a}\right )+\frac {x \arctan (a x)^{3/2}}{4 \left (a^2 x^2+1\right )^2}+\frac {3 \sqrt {\arctan (a x)}}{32 a \left (a^2 x^2+1\right )^2}-\frac {3 \left (\frac {1}{8} \sqrt {\frac {\pi }{2}} \operatorname {FresnelC}\left (2 \sqrt {\frac {2}{\pi }} \sqrt {\arctan (a x)}\right )+\frac {1}{2} \sqrt {\pi } \operatorname {FresnelC}\left (\frac {2 \sqrt {\arctan (a x)}}{\sqrt {\pi }}\right )+\frac {3}{4} \sqrt {\arctan (a x)}\right )}{64 a}\right )}{8 a c^3}-\frac {\arctan (a x)^{5/2}}{4 a^2 c^3 \left (a^2 x^2+1\right )^2}\)

input
Int[(x*ArcTan[a*x]^(5/2))/(c + a^2*c*x^2)^3,x]
 
output
-1/4*ArcTan[a*x]^(5/2)/(a^2*c^3*(1 + a^2*x^2)^2) + (5*((3*Sqrt[ArcTan[a*x] 
])/(32*a*(1 + a^2*x^2)^2) + (x*ArcTan[a*x]^(3/2))/(4*(1 + a^2*x^2)^2) - (3 
*((3*Sqrt[ArcTan[a*x]])/4 + (Sqrt[Pi/2]*FresnelC[2*Sqrt[2/Pi]*Sqrt[ArcTan[ 
a*x]]])/8 + (Sqrt[Pi]*FresnelC[(2*Sqrt[ArcTan[a*x]])/Sqrt[Pi]])/2))/(64*a) 
 + (3*((x*ArcTan[a*x]^(3/2))/(2*(1 + a^2*x^2)) + ArcTan[a*x]^(5/2)/(5*a) - 
 (3*a*(-1/2*Sqrt[ArcTan[a*x]]/(a^2*(1 + a^2*x^2)) + (Sqrt[ArcTan[a*x]] + ( 
Sqrt[Pi]*FresnelC[(2*Sqrt[ArcTan[a*x]])/Sqrt[Pi]])/2)/(4*a^2)))/4))/4))/(8 
*a*c^3)
 

3.9.75.3.1 Defintions of rubi rules used

rule 27
Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 2009
Int[u_, x_Symbol] :> Simp[IntSum[u, x], x] /; SumQ[u]
 

rule 3042
Int[u_, x_Symbol] :> Int[DeactivateTrig[u, x], x] /; FunctionOfTrigOfLinear 
Q[u, x]
 

rule 3793
Int[((c_.) + (d_.)*(x_))^(m_)*sin[(e_.) + (f_.)*(x_)]^(n_), x_Symbol] :> In 
t[ExpandTrigReduce[(c + d*x)^m, Sin[e + f*x]^n, x], x] /; FreeQ[{c, d, e, f 
, m}, x] && IGtQ[n, 1] && ( !RationalQ[m] || (GeQ[m, -1] && LtQ[m, 1]))
 

rule 5427
Int[((a_.) + ArcTan[(c_.)*(x_)]*(b_.))^(p_.)/((d_) + (e_.)*(x_)^2)^2, x_Sym 
bol] :> Simp[x*((a + b*ArcTan[c*x])^p/(2*d*(d + e*x^2))), x] + (Simp[(a + b 
*ArcTan[c*x])^(p + 1)/(2*b*c*d^2*(p + 1)), x] - Simp[b*c*(p/2)   Int[x*((a 
+ b*ArcTan[c*x])^(p - 1)/(d + e*x^2)^2), x], x]) /; FreeQ[{a, b, c, d, e}, 
x] && EqQ[e, c^2*d] && GtQ[p, 0]
 

rule 5435
Int[((a_.) + ArcTan[(c_.)*(x_)]*(b_.))^(p_)*((d_) + (e_.)*(x_)^2)^(q_), x_S 
ymbol] :> Simp[b*p*(d + e*x^2)^(q + 1)*((a + b*ArcTan[c*x])^(p - 1)/(4*c*d* 
(q + 1)^2)), x] + (-Simp[x*(d + e*x^2)^(q + 1)*((a + b*ArcTan[c*x])^p/(2*d* 
(q + 1))), x] + Simp[(2*q + 3)/(2*d*(q + 1))   Int[(d + e*x^2)^(q + 1)*(a + 
 b*ArcTan[c*x])^p, x], x] - Simp[b^2*p*((p - 1)/(4*(q + 1)^2))   Int[(d + e 
*x^2)^q*(a + b*ArcTan[c*x])^(p - 2), x], x]) /; FreeQ[{a, b, c, d, e}, x] & 
& EqQ[e, c^2*d] && LtQ[q, -1] && GtQ[p, 1] && NeQ[q, -3/2]
 

rule 5439
Int[((a_.) + ArcTan[(c_.)*(x_)]*(b_.))^(p_.)*((d_) + (e_.)*(x_)^2)^(q_), x_ 
Symbol] :> Simp[d^q/c   Subst[Int[(a + b*x)^p/Cos[x]^(2*(q + 1)), x], x, Ar 
cTan[c*x]], x] /; FreeQ[{a, b, c, d, e, p}, x] && EqQ[e, c^2*d] && ILtQ[2*( 
q + 1), 0] && (IntegerQ[q] || GtQ[d, 0])
 

rule 5465
Int[((a_.) + ArcTan[(c_.)*(x_)]*(b_.))^(p_.)*(x_)*((d_) + (e_.)*(x_)^2)^(q_ 
.), x_Symbol] :> Simp[(d + e*x^2)^(q + 1)*((a + b*ArcTan[c*x])^p/(2*e*(q + 
1))), x] - Simp[b*(p/(2*c*(q + 1)))   Int[(d + e*x^2)^q*(a + b*ArcTan[c*x]) 
^(p - 1), x], x] /; FreeQ[{a, b, c, d, e, q}, x] && EqQ[e, c^2*d] && GtQ[p, 
 0] && NeQ[q, -1]
 
3.9.75.4 Maple [A] (verified)

Time = 1.82 (sec) , antiderivative size = 157, normalized size of antiderivative = 0.62

\[-\frac {1024 \arctan \left (a x \right )^{\frac {5}{2}} \cos \left (2 \arctan \left (a x \right )\right ) \sqrt {\pi }+256 \arctan \left (a x \right )^{\frac {5}{2}} \cos \left (4 \arctan \left (a x \right )\right ) \sqrt {\pi }-1280 \arctan \left (a x \right )^{\frac {3}{2}} \sin \left (2 \arctan \left (a x \right )\right ) \sqrt {\pi }+15 \pi \sqrt {2}\, \operatorname {FresnelC}\left (\frac {2 \sqrt {2}\, \sqrt {\arctan \left (a x \right )}}{\sqrt {\pi }}\right )-160 \arctan \left (a x \right )^{\frac {3}{2}} \sqrt {\pi }\, \sin \left (4 \arctan \left (a x \right )\right )-960 \sqrt {\arctan \left (a x \right )}\, \sqrt {\pi }\, \cos \left (2 \arctan \left (a x \right )\right )+480 \pi \,\operatorname {FresnelC}\left (\frac {2 \sqrt {\arctan \left (a x \right )}}{\sqrt {\pi }}\right )-60 \cos \left (4 \arctan \left (a x \right )\right ) \sqrt {\arctan \left (a x \right )}\, \sqrt {\pi }}{8192 c^{3} a^{2} \sqrt {\pi }}\]

input
int(x*arctan(a*x)^(5/2)/(a^2*c*x^2+c)^3,x)
 
output
-1/8192/c^3/a^2/Pi^(1/2)*(1024*arctan(a*x)^(5/2)*cos(2*arctan(a*x))*Pi^(1/ 
2)+256*arctan(a*x)^(5/2)*cos(4*arctan(a*x))*Pi^(1/2)-1280*arctan(a*x)^(3/2 
)*sin(2*arctan(a*x))*Pi^(1/2)+15*Pi*2^(1/2)*FresnelC(2*2^(1/2)/Pi^(1/2)*ar 
ctan(a*x)^(1/2))-160*arctan(a*x)^(3/2)*Pi^(1/2)*sin(4*arctan(a*x))-960*arc 
tan(a*x)^(1/2)*Pi^(1/2)*cos(2*arctan(a*x))+480*Pi*FresnelC(2*arctan(a*x)^( 
1/2)/Pi^(1/2))-60*cos(4*arctan(a*x))*arctan(a*x)^(1/2)*Pi^(1/2))
 
3.9.75.5 Fricas [F(-2)]

Exception generated. \[ \int \frac {x \arctan (a x)^{5/2}}{\left (c+a^2 c x^2\right )^3} \, dx=\text {Exception raised: TypeError} \]

input
integrate(x*arctan(a*x)^(5/2)/(a^2*c*x^2+c)^3,x, algorithm="fricas")
 
output
Exception raised: TypeError >>  Error detected within library code:   inte 
grate: implementation incomplete (constant residues)
 
3.9.75.6 Sympy [F]

\[ \int \frac {x \arctan (a x)^{5/2}}{\left (c+a^2 c x^2\right )^3} \, dx=\frac {\int \frac {x \operatorname {atan}^{\frac {5}{2}}{\left (a x \right )}}{a^{6} x^{6} + 3 a^{4} x^{4} + 3 a^{2} x^{2} + 1}\, dx}{c^{3}} \]

input
integrate(x*atan(a*x)**(5/2)/(a**2*c*x**2+c)**3,x)
 
output
Integral(x*atan(a*x)**(5/2)/(a**6*x**6 + 3*a**4*x**4 + 3*a**2*x**2 + 1), x 
)/c**3
 
3.9.75.7 Maxima [F(-2)]

Exception generated. \[ \int \frac {x \arctan (a x)^{5/2}}{\left (c+a^2 c x^2\right )^3} \, dx=\text {Exception raised: RuntimeError} \]

input
integrate(x*arctan(a*x)^(5/2)/(a^2*c*x^2+c)^3,x, algorithm="maxima")
 
output
Exception raised: RuntimeError >> ECL says: expt: undefined: 0 to a negati 
ve exponent.
 
3.9.75.8 Giac [F]

\[ \int \frac {x \arctan (a x)^{5/2}}{\left (c+a^2 c x^2\right )^3} \, dx=\int { \frac {x \arctan \left (a x\right )^{\frac {5}{2}}}{{\left (a^{2} c x^{2} + c\right )}^{3}} \,d x } \]

input
integrate(x*arctan(a*x)^(5/2)/(a^2*c*x^2+c)^3,x, algorithm="giac")
 
output
sage0*x
 
3.9.75.9 Mupad [F(-1)]

Timed out. \[ \int \frac {x \arctan (a x)^{5/2}}{\left (c+a^2 c x^2\right )^3} \, dx=\int \frac {x\,{\mathrm {atan}\left (a\,x\right )}^{5/2}}{{\left (c\,a^2\,x^2+c\right )}^3} \,d x \]

input
int((x*atan(a*x)^(5/2))/(c + a^2*c*x^2)^3,x)
 
output
int((x*atan(a*x)^(5/2))/(c + a^2*c*x^2)^3, x)